Тема: LIMIT
result = mysql_query("SELECT * FROM table_reviews,table_one WHERE table_one.id_image = table_reviews.id_image ORDER BY $sort LIMIT $start, $num",$link)or die(mysql_error());
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LIMIT 0, 4' at line
Не можу виправити і зрозуміти в чому проблема